How does the set of complex numbers (resp., nonzero complex numbers) form a group under addition (resp., multiplication)?

$\begingroup$ @chisom chinwuko: Assuming, as Ross does, that you meant "the set of all complex numbers" and "the set of all complex numbers without zero", then the answer is: in the obvious way. $\endgroup$

Commented Dec 5, 2010 at 22:09 $\begingroup$ The title should be changed. $\endgroup$ Commented Dec 5, 2010 at 22:58

1 Answer 1

$\begingroup$

A complex number is not a group under addition. The set of all complex numbers is a group under addition. Just look at the definition of a group and see that you can verify the axioms. Similarly for the set of complex numbers without zero and multiplication.

answered Dec 5, 2010 at 22:04 Ross Millikan Ross Millikan 379k 27 27 gold badges 259 259 silver badges 457 457 bronze badges

You must log in to answer this question.

Related

Hot Network Questions

Subscribe to RSS

Question feed

To subscribe to this RSS feed, copy and paste this URL into your RSS reader.

Site design / logo © 2024 Stack Exchange Inc; user contributions licensed under CC BY-SA . rev 2024.9.11.15092